Check sibling questions
Chapter 14 Class 10 Statistics
Serial order wise

Question

The weights (in kg) of 50 wrestlers are recorded in the following table:

Weight (in Kg)

100 − 110

110 − 120

120−130

130−140

140−150

No. of Wrestles

4

14

21

8

3

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Question 1

What is the upper limit of modal class. 

(a) 120  

(b) 130

(c) 100  

(d) 150

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Question 2 

What is the mode class frequency of the given data 

(a) 21  

(b) 50

(c) 25  

(d) 80

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Question 3

How many wrestlers weights have more than 120 kg weight? 

(a) 32  

(b) 50

(c) 16  

(d) 21

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Question 4

What is the class mark for class 130 – 140? 

(a) 120  

(b) 130

(c) 135  

(d) 150

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Question 5

Which method is more suitable to find the mean of the above data? 

(a) Direct method  

(b) Assumed mean method 

(c) Step-Deviation method  

(d) None of these

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Transcript

Question The weights (in kg) of 50 wrestlers are recorded in the following table: Question 1 What is the upper limit of modal class. (a) 120 (b) 130 (c) 100 (d) 150 Modal class is class with highest frequency Since 120 – 130 has highest frequency 21 ∴ It is the modal class Upper limit = 130 So, the correct answer is (b) Question 2 What is the mode class frequency of the given data (a) 21 (b) 50 (c) 25 (d) 80 From Question 1 The modal class is 120 – 130 So, The mode class frequency = 21 So, the correct answer is (a) Question 3 How many wrestlers weights have more than 120 kg weight? (a) 32 (b) 50 (c) 16 (d) 21 Number of wrestlers with weight more than 120kg = 21 + 8 + 3 = 32 So, the correct answer is (a) Question 4 What is the class mark for class 130 – 140? (a) 120 (b) 130 (c) 135 (d) 150 Class mark of 130 – 140 = (130 + 140)/2 = 270/2 = 135 So, the correct answer is (c) Question 5 Which method is more suitable to find the mean of the above data? (a) Direct method (b) Assumed mean method (c) Step-Deviation method (d) None of these Checking all options (a) Direct method – In this method, we have to do a lot of multiplication, which may result in calculation error. So, we won’t use this method (b) Assumed Mean method – In this method, the calculation will still be lengthy So, we won’t use this method (c) Step-Deviation method – In this method, the calculations will be easier as class size is equal for all classes. So, we can divide easily. Thus, we will use this method So, the correct answer is (C)

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.