it is denoted by

v
^{
2
}
- u
^{
2
}
= 2as

Where

v = Final Velocity

u = Initial Velocity

s = Distance Travelled

a = acceleration

To solve problems using equations of motion, we should remember that

- If body starts from rest, its Initial velocity = u = 0
- If we drop a body from some height, its Initial velocity = u = 0
- If body stops, its Final velocity = v = 0
- If body moves with uniform velocity, its Acceleration = a = 0

## Questions

**
Q 2 Page 110 -
**
A train is traveling at a speed of 90 km h–1. Brakes are applied so as to produce a uniform acceleration of – 0.5 m s-2. Find how far the train will go before it is brought to rest.

**
Q 5 Page 110 -
**
A stone is thrown in a vertically upward direction with a velocity of 5 m s-1. If the acceleration of the stone during its motion is 10 m s–2 in the downward direction, what will be the height attained by the stone and how much time will it take to reach there?

**
NCERT Question 7 -
**
A ball is gently dropped from a height of 20 m. If its velocity increases uniformly at the rate of 10 m s-2, with what velocity will it strike the ground? After what time will it strike the ground?

**
Example 8.5 -
**
A train starting from rest attains a velocity of 72 km h–1 in5 minutes. Assuming that the acceleration is uniform, find (i) the acceleration and (ii) the distance travelled by the train for attaining this velocity.