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Chapter 8 Class 9 - Motion

Question 1 - Graph Question (Easy) - Teachoo Questions - Chapter 8 Class 9 - Motion

Last updated at May 29, 2023 by

Find Displacement and Acceleration in region OA and OB. Also tell the type of motion in both the regions. And find the total displacement

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Marking point C in the graph

Β 

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Motion in region OA = Uniformly accelerated

Motion in region OB = Uniformly retarded

Β Total Displacement = Area of βˆ†ABO

Β = Area of βˆ†OAC + Area of βˆ†ABC

Β = 4m + 4m

Β = 8mΒ Β 

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Transcript

Region OA Acceleration = Slope of OA = (𝑦_2 βˆ’ 𝑦_1)/(π‘₯_2 βˆ’ π‘₯_1 ) = (4 βˆ’ 0)/(2 βˆ’ 0) = 4/2 = 2 m/s2 Displacement = Area under v – t graph = Area of βˆ†OAC = 1/2 Γ— b Γ— h = 1/2 Γ— 2 Γ— 4 = 4 m Region AB Acceleration = Slope of BA = (𝑦_2 βˆ’ 𝑦_1)/(π‘₯_2 βˆ’ π‘₯_1 ) = (0 βˆ’ 4)/(0 βˆ’ 2) = (βˆ’4)/2 = βˆ’2 m/s2 Displacement = Area under v – t graph = Area of βˆ†ABC = 1/2 Γ— b Γ— h = 1/2 Γ— 2 Γ— 4 = 4 km

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