Find Displacement and Acceleration in region OA and OB. Also tell the type of motion in both the regions. And find the total displacement

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Marking point C in the graph

 

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Motion in region OA = Uniformly accelerated

Motion in region OB = Uniformly retarded

 Total Displacement = Area of โˆ†ABO

 = Area of โˆ†OAC + Area of โˆ†ABC

 = 4m + 4m

 = 8m  

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  1. Class 9
  2. Chapter 8 Class 9 - Motion

Transcript

Region OA Acceleration = Slope of OA = (๐‘ฆ_2 โˆ’ ๐‘ฆ_1)/(๐‘ฅ_2 โˆ’ ๐‘ฅ_1 ) = (4 โˆ’ 0)/(2 โˆ’ 0) = 4/2 = 2 m/s2 Displacement = Area under v โ€“ t graph = Area of โˆ†OAC = 1/2 ร— b ร— h = 1/2 ร— 2 ร— 4 = 4 m Region AB Acceleration = Slope of BA = (๐‘ฆ_2 โˆ’ ๐‘ฆ_1)/(๐‘ฅ_2 โˆ’ ๐‘ฅ_1 ) = (0 โˆ’ 4)/(0 โˆ’ 2) = (โˆ’4)/2 = โˆ’2 m/s2 Displacement = Area under v โ€“ t graph = Area of โˆ†ABC = 1/2 ร— b ร— h = 1/2 ร— 2 ร— 4 = 4 km

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.