Question 1 - Graph Question (Easy) - Teachoo Questions - Chapter 8 Class 9 - Motion

Last updated at August 13, 2026 by

Find Displacement and Acceleration in region OA and OB. Also tell the type of motion in both the regions. And find the total displacement

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Marking point C in the graph

ย 

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Velocity-Time Graph Question - Easy - Practice Questions - Teachoo - Teachoo Questions

Motion in region OA = Uniformly accelerated

Motion in region OB = Uniformly retarded

ย Total Displacement = Area of โˆ†ABO

ย = Area of โˆ†OAC + Area of โˆ†ABC

ย = 4m + 4m

ย = 8mย ย 

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Transcript

Region OA Acceleration = Slope of OA = (๐‘ฆ_2 โˆ’ ๐‘ฆ_1)/(๐‘ฅ_2 โˆ’ ๐‘ฅ_1 ) = (4 โˆ’ 0)/(2 โˆ’ 0) = 4/2 = 2 m/s2 Displacement = Area under v โ€“ t graph = Area of โˆ†OAC = 1/2 ร— b ร— h = 1/2 ร— 2 ร— 4 = 4 m Region AB Acceleration = Slope of BA = (๐‘ฆ_2 โˆ’ ๐‘ฆ_1)/(๐‘ฅ_2 โˆ’ ๐‘ฅ_1 ) = (0 โˆ’ 4)/(0 โˆ’ 2) = (โˆ’4)/2 = โˆ’2 m/s2 Displacement = Area under v โ€“ t graph = Area of โˆ†ABC = 1/2 ร— b ร— h = 1/2 ร— 2 ร— 4 = 4 km

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