Find Displacement and Acceleration from Time 0-2 seconds, 2-10 secs, 10-12 seconds, 12-16 seconds. Also tell the type of motion in all the regions. And find the total displacement

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Let’s mark the points and their coordinates

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Motion in region OA = Uniformly accelerated

Motion in region AB = Uniformly motion (No acceleration)

Motion in region BC = Uniformly retarded

Motion in region CD = Uniformly motion (No acceleration)

Total displacement

   = Displacement in OA + Displacement in AB

     + Displacement in BC + Displacement in CD

  = 8 + 64 + 12 + 16

  = 100 m

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Transcript

In 2 āˆ’ 10 seconds (Region AB) Acceleration = Slope of AB = (š‘¦_2 āˆ’ š‘¦_1)/(š‘„_2 āˆ’ š‘„_1 ) = (8 āˆ’ 8)/(2 āˆ’ 0) = 0/2 = 0 m/s2 Displacement = Area under v – t graph = Area of rectangle ABQP = Length Ɨ Breadth = AP Ɨ AB = 8 Ɨ 8 = 64 m In 10 āˆ’ 12 seconds (Region BC) Acceleration = Slope of BC = (š‘¦_2 āˆ’ š‘¦_1)/(š‘„_2 āˆ’ š‘„_1 ) = (4 āˆ’ 8)/(12 āˆ’ 10) = (āˆ’4)/2 = –2 m/s2 Acceleration = Slope of BC = (š‘¦_2 āˆ’ š‘¦_1)/(š‘„_2 āˆ’ š‘„_1 ) = (4 āˆ’ 8)/(12 āˆ’ 10) = (āˆ’4)/2 = –2 m/s2 In 12 āˆ’ 16 seconds (Region CD) Acceleration = Slope of OA = (š‘¦_2 āˆ’ š‘¦_1)/(š‘„_2 āˆ’ š‘„_1 ) = (4 āˆ’ 4)/(16 āˆ’12) = 0/4 = 0 m/s2 Displacement = Area of rectangle CDSR = Length Ɨ Breadth = CD Ɨ CR = 4 Ɨ 4 = 16 m

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