Class 9
Chapter 8 Class 9 - Motion

Find Displacement and Acceleration from Time 0-2 seconds, 2-10 secs, 10-12 seconds, 12-16 seconds. Also tell the type of motion in all the regions. And find the total displacement

slide6.jpg

Let’s mark the points and their coordinates

slide7.jpg

Slide8.JPG Slide9.JPG Slide10.JPG Slide11.JPG

Motion in region OA = Uniformly accelerated

Motion in region AB = Uniformly motion (No acceleration)

Motion in region BC = Uniformly retarded

Motion in region CD = Uniformly motion (No acceleration)

Total displacement

   = Displacement in OA + Displacement in AB

     + Displacement in BC + Displacement in CD

  = 8 + 64 + 12 + 16

  = 100 m

Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class


Transcript

In 2 − 10 seconds (Region AB) Acceleration = Slope of AB = (𝑦_2 − 𝑦_1)/(𝑥_2 − 𝑥_1 ) = (8 − 8)/(2 − 0) = 0/2 = 0 m/s2 Displacement = Area under v – t graph = Area of rectangle ABQP = Length × Breadth = AP × AB = 8 × 8 = 64 m In 10 − 12 seconds (Region BC) Acceleration = Slope of BC = (𝑦_2 − 𝑦_1)/(𝑥_2 − 𝑥_1 ) = (4 − 8)/(12 − 10) = (−4)/2 = –2 m/s2 Acceleration = Slope of BC = (𝑦_2 − 𝑦_1)/(𝑥_2 − 𝑥_1 ) = (4 − 8)/(12 − 10) = (−4)/2 = –2 m/s2 In 12 − 16 seconds (Region CD) Acceleration = Slope of OA = (𝑦_2 − 𝑦_1)/(𝑥_2 − 𝑥_1 ) = (4 − 4)/(16 −12) = 0/4 = 0 m/s2 Displacement = Area of rectangle CDSR = Length × Breadth = CD × CR = 4 × 4 = 16 m

Ask a doubt
Maninder Singh's photo - Co-founder, Teachoo

Made by

Maninder Singh

CA Maninder Singh is a Chartered Accountant for the past 13 years and a teacher from the past 17 years. He teaches Science, Economics, Accounting and English at Teachoo