Example 9 - Chapter 5 Class 11 Linear Inequalities
Last updated at Dec. 16, 2024 by Teachoo
Last updated at Dec. 16, 2024 by Teachoo
Example 9 Solve – 8 ≤ 5x – 3 < 7. –8 ≤ 5x – 3 < 7 Adding 3 all sides (Eliminating -3) – 8 + 3 ≤ 5x – 3 + 3 < 7 + 3 –5 ≤ 5x < 10 Dividing 5 all sides (Eliminating 5) (−5)/5 ≤ 5𝑥/5 < 10/5 –1 ≤ x < 2 Thus, x is a real number which is less than 2 and greater than or equal to –1 Hence, x ∈ [–1, 2) is the solution
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo