Ex 5.1, 4 - Chapter 5 Class 11 Linear Inequalities
Last updated at Dec. 16, 2024 by Teachoo
Last updated at Dec. 16, 2024 by Teachoo
Ex 5.1, 4 Solve 3x + 8 > 2, when x is an integer 3x + 8 > 2 3x > 2 โ 8 3x > โ6 ๐ฅ > (โ6)/3 ๐ฅ > โ2 Since x is an integer (โฆโฆ,โ3, โ2, โ1, 0, 1, 2, 3โฆ.) We need to find values of x which is greater than -2 i.e. x can be -1, 0, 1, 2, 3, 4,โฆโฆ.. = {โ1, 0, 1, 2, 3, 4,โฆโฆ} Integers: โฆ..,โ2, โ1, 0, 1, 2, 3,โฆ. Ex 5.1, 4 Solve 3x + 8 > 2, when (ii) x is a real number Now, x > โ2 Since x is a real number which is greater than โ2 Thus x โ (โ2, โ)
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