Ex 5.1, 2 - Chapter 5 Class 11 Linear Inequalities
Last updated at Dec. 16, 2024 by Teachoo
Last updated at Dec. 16, 2024 by Teachoo
Ex 5.1, 2 Solve 12x > 30, when x is a natural number 12x > 30 x > 30 12 x > 2.5 Since x is negative, we multiply both sides by -1 & change the signs ( x) (-1) < 2.5 (-1) x < 2.5 (i) Since x is a natural number, it can be only positive number starting from 1 (i.e. 1, 2, 3, 4, 5, .) There is no natural number less than 2.5. Thus, when x is a natural number, there is no solution. (ii) x is an integer Now, x < 2.5 Since x is an integer, it can be negative but cannot be a decimal So, x can be any negative number less than 3 Hence, the values of x which will satisfy the inequality are = { , 6, 5, 4, 3}
Ex 5.1
Ex 5.1, 2 You are here
Ex 5.1, 3
Ex 5.1, 4 Important
Ex 5.1, 5
Ex 5.1, 6 Important
Ex 5.1, 7
Ex 5.1, 8 Important
Ex 5.1, 9
Ex 5.1, 10 Important
Ex 5.1, 11 Important
Ex 5.1, 12
Ex 5.1, 13
Ex 5.1, 14
Ex 5.1, 15
Ex 5.1, 16 Important
Ex 5.1, 17 Important
Ex 5.1, 18
Ex 5.1, 19
Ex 5.1, 20 Important
Ex 5.1, 21
Ex 5.1, 22 Important
Ex 5.1, 23 Important
Ex 5.1, 24
Ex 5.1, 25 Important
Ex 5.1, 26
About the Author
Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo