Ex 5.6, 2 - Chapter 5 Class 12 Continuity and Differentiability
Last updated at Dec. 16, 2024 by Teachoo
Last updated at Dec. 16, 2024 by Teachoo
Ex 5.6, 2 If x and y are connected parametrically by the equations without eliminating the parameter, Find ππ¦/ππ₯, π₯=π cosβ‘π, π¦=π cosβ‘πHere ππ¦/ππ₯ = (ππ¦/ππ)/(ππ₯/ππ) Calculating π π/π π½ π¦ = π cosβ‘π ππ¦/ππ = π(π πππ β‘π)/ππ ππ¦/ππ = b . (βsinβ‘π ) π π/π π½ = β π π¬π’π§ π½ Calculating π π/π π½ π₯=π cosβ‘π ππ₯/ππ = π(π cosβ‘π )/ππ ππ₯/ππ = π . (βsinβ‘π ) π π/π π½ = βπ πππβ‘π½
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