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Ex 4.5, 4 Examine the consistency of the system of equations. x + y + z = 1 2x + 3y + 2z = 2 ax + ay + 2az = 4 Simplifying 3rd equation ax + ay + 2az = 4 a(x + y + 2z) = 4 x + y + 2z = 4/๐‘Ž Now System of equation is x + y + z = 1 2x + 3y + 2z = 2 x + y + 2y = 4/๐‘Ž Writing equation as AX = B [โ– 8(1&1&1@2&3&2@1&1&2)] [โ– 8(๐‘ฅ@๐‘ฆ@๐‘ง)] = [โ– 8(1@2@4/๐‘Ž)] Hence, A = [โ– 8(1&1&1@2&3&2@1&1&2)] , X =[โ– 8(๐‘ฅ@๐‘ฆ@๐‘ง)] & B =[โ– 8(1@2@4/๐‘Ž)] Calculating |A| |A| = |โ– 8(1&1&1@2&3&2@1&1&2)| = 1 |โ– 8(3&2@1&2)| โ€“1 |โ– 8(2&2@1&2)| +1|โ– 8(2&3@1&1)| = 1(6 โ€“ 2) โ€“ 1(4 โ€“ 2) + 1 (2 โ€“ 3) = 4 โ€“ 2 โ€“ 1 = 1 โ‰  0 Since |A| โ‰  0 Hence system of equation is consistent

  1. Chapter 4 Class 12 Determinants
  2. Serial order wise

About the Author

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo