Last updated at Dec. 13, 2024 by Teachoo
Example 11 Prove that cotβ‘γπ΄ β cosβ‘π΄ γ/cotβ‘γπ΄ + cosβ‘π΄ γ =(πππ ππ π΄ β 1)/(πππ ππ π΄ + 1) Taking L.H.S cotβ‘γπ΄ βγ cosγβ‘π΄ γ/cotβ‘γπ΄ +γ cosγβ‘π΄ γ Writing everything in terms of sin A and cos A = (cosβ‘γ π΄γ/sinβ‘γ π΄γ βγ cosγβ‘γ π΄γ)/(cosβ‘γ π΄γ/sinβ‘γ π΄γ +γ cosγβ‘γ π΄γ ) = cosβ‘γ π΄ βγ cosγβ‘γ π΄ sinβ‘γ π΄γ γ γ/(sinβ‘γ π΄γ/(cosβ‘γ π΄ + cosβ‘γ π΄ sinβ‘γ π΄γ γ γ/sinβ‘γ π΄γ )) = ( (πππβ‘γ π¨γ β πππβ‘γ π¨γ sinβ‘γ π΄ γ))/((πππβ‘γ π¨γ + πππβ‘γ π¨γ sinβ‘γ π΄ γ)) = (πππβ‘γ π¨γ (1 β sinβ‘γ π΄ γ))/(πππβ‘γ π¨γ (1 + sinβ‘γ π΄ γ)) = ( (1 β sinβ‘γ π΄ γ))/( (1 + sinβ‘γ π΄ γ)) Dividing sin A on numerator and denominator = ( ((1 β sinβ‘γ π΄ γ))/(πππ π¨))/( ((1 + sinβ‘γ π΄ γ))/(πππ π¨ )) = ( 1/(π ππ π΄) β (π ππ π΄)/(π ππ π΄))/(1/(π ππ π΄) + (π ππ π΄)/(π ππ π΄)) = ( 1/(π ππ π΄) β 1)/(1/(π ππ π΄) + 1) = (πππππ π¨ β π)/(πππππ π¨ + π) = R.H.S. So, L.H.S = R.H.S Hence proved
About the Author
Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo