Ex 14.4, 13 - Find and correct (2a + 3b) (a - b) = 2a^2 - 3b^2

Ex 14.4, 13 - Chapter 14 Class 8 Factorisation - Part 2

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Question 13 Find and correct the errors in the following mathematical statements. (2a + 3b) (a – b) = 2š‘Ž^2 – 3š‘^2 (2a + 3b) (a – b) = 2š‘Ž^2 – 3š‘^2 Solving L.H.S : (2a + 3b) (a – b) = 2a (a āˆ’ b) + 3b (a āˆ’ b) = (2a Ɨ a) āˆ’ (2a Ɨ b) + (3b Ɨ a) āˆ’ (3b Ɨ b) = 怖2š‘Žć€—^2 āˆ’ 2ab + 3ba āˆ’ 怖3š‘ć€—^2 = 怖2š‘Žć€—^2 āˆ’ 2ab + 3ab āˆ’ 怖3š‘ć€—^2 Taking ab common = 怖2š‘Žć€—^2 + ab (āˆ’2 + 3) āˆ’ 怖3š‘ć€—^2 (Since 3ba = 3ab) = 怖2š‘Žć€—^2 + ab āˆ’ 怖3š‘ć€—^2 ∓ (2a + 3b) (a āˆ’ b) = ć€–šŸš’‚ć€—^šŸ + ab āˆ’ ć€–šŸ‘š’ƒć€—^šŸ is the correct statement

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