Slide3.JPG

Go Ad-free

Transcript

Ex 12.3, 1 Carry out the following divisions. (iii) 66ใ€–๐‘๐‘žใ€—^2 ๐‘Ÿ^3 รท 11ใ€–๐‘ž๐‘Ÿใ€—^266ใ€–๐‘๐‘žใ€—^2 ๐‘Ÿ^3 รท 11ใ€–๐‘ž๐‘Ÿใ€—^2 = (66๐‘๐‘ž^2 ๐‘Ÿ^3)/(11๐‘ž๐‘Ÿ^2 ) = ๐Ÿ”๐Ÿ”/๐Ÿ๐Ÿ ร— p ร— ๐’’^๐Ÿ/๐’’ ร— ๐’“^๐Ÿ‘/๐’“^๐Ÿ = 6 ร— p ร— ๐‘ž^(2 โˆ’ 1) ร— ๐‘Ÿ^(3 โˆ’ 2) = 6 ร— p ร— q ร— r = 6pqr (( ๐‘Ž^๐‘š)/๐‘Ž^๐‘› " = " ๐‘Ž^(๐‘š โˆ’๐‘›) " " )

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.