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Ex 11.3, 4 - Rukhsar painted the outside of the cabinet of measure 1 m

Ex 11.3, 4 - Chapter 11 Class 8 Mensuration - Part 2
Ex 11.3, 4 - Chapter 11 Class 8 Mensuration - Part 3

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Transcript

Ex 11.3, 4 Rukhsar painted the outside of the cabinet of measure 1 m Γ— 2 m Γ— 1.5 m. How much surface area did she cover if she painted all except the bottom of the cabinet. Given cabinet is a cuboid with Length (𝑙) = 2 m Breadth (𝑏) = 1 m Height (β„Ž) = 1.5 m Rukhsar painted all except the bottom of the cabinet Area Painted = So, Area Painted = Total surface Area of Cabinet – Area of bottom Total surface area of cabinet Area = Total surface area of cuboid = 2(𝑙𝑏+π‘β„Ž+β„Žπ‘™) = 2(2Γ—1+1Γ—1.5+1.5Γ—2) = 2(2+1.5+3) = 2(6.5) = 13 m2 Bottom area of cabinet Area = Length Γ— Breadth = 2 Γ— 1 = 2 m2 Thus, Area she painted = Total surface area βˆ’ Bottom area = 13 – 2 = 11 m2

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.