Ex 9.2, 1 There are two cuboidal boxes as shown in the adjoining figure. Which box requires the lesser amount of material to make?The box with lesser total surface area will require lesser amount of material to make.
Letβs find total surface area of both boxes
Total Surface Area of Box (a)
This box is a cuboid with
Length = l = 60 cm
Breadth = b = 60 cm
Height = h = 60 cm
Total surface area of box
= Total surface area of cuboid
= π(ππ+ππ+ππ)
Total Surface Area of Box (b)
This box is a cube with
Side = a = 50 cm
Total surface area of box
= Total surface area of cube
= ππ^π
= 6Γ(50)^2 = 6Γ50Γ50
= 6Γ2500 = πππππ ππ^π
= 2(60Γ40+40Γ50+50Γ60)
= 2(2400+2000+3000)
= 2Γ74000.
= ππππππ ππ^π
Since total surface area of box (a) is lesser than the total surface area of box (b).
β΄ Box (a) requires lesser amount of material to make.

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.

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