Check sibling questions

Ex 11.3, 2 - A suitcase with measures 80 cm x 48 cm x 24 cm is to be

Ex 11.3, 2 - Chapter 11 Class 8 Mensuration - Part 2
Ex 11.3, 2 - Chapter 11 Class 8 Mensuration - Part 3
Ex 11.3, 2 - Chapter 11 Class 8 Mensuration - Part 4

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Transcript

Ex 11.3, 2 A suitcase with measures 80 cm Γ— 48 cm Γ— 24 cm is to be covered with a tarpaulin cloth. How many meters of tarpaulin of width 96 cm is required to cover 100 such suitcases? Given, Length of suitcase = 𝑙 = 80 cm Breadth of suitcase = 𝑏 = 48 cm & Height of suitcase = β„Ž = 24 cm As tarpaulin cloth covers the suitcase. ∴ Area of cloth required to cover 1 suitcase = Total surface area of 1 suitcase Total surface area of 1 suitcase = Total surface area of cuboid = 2(𝑙𝑏+π‘β„Ž+β„Žπ‘™) = 2(80Γ—48+48Γ—24+24Γ—80) = 2(3840+1152+1920) = 2Γ—6912 = 13824 π‘π‘š^2 Now, we need to find how many meters of tarpaulin of width 96 cm is required to cover 100 such suitcases So, Area of tarpaulin = 100 Γ— Area of 1 suitcase Since Tarpaulin is a rectangle with Width = 96 cm and Length we need to find So, Area of tarpaulin = 100 Γ— Area of 1 suitcase 96 Γ— Length = 100 Γ— 13824 Length = 100 Γ— 13824/96 Length = 100 Γ— 6912/48 = 100 Γ— 3456/24 = 100 Γ— 1728/12 = 100 Γ— 144 Length = 14400 cm Length = 14400 cm Length = 14400 Γ— 1/100 m Length = 144 m ∴ 144 m of cloth is required.

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.