To find area of any general quadrilateral,
We split it into triangles and add their area parallelogram has opposites sides equal & parallel
For Quadrilateral ABCD
We join AC
So, we have two triangles - Δ ADC and Δ ABC
Let h 1 be height from point D to AC
& h 2 be height from point B to AC
So,
Area of Quadrilateral ABCD
= Area of Δ ADC + Area of Δ ABC
= 1/2 × AC × h 1 + 1/2 × AC × h 2
= 1/2 × AC × (h 1 + h 2 )
= 1/2 × d (h 1 + h 2 )
where d = Length of Diagonal
Find area of quadrilateral ABCD
Given
Length of diagonal = d = 10 cm
Length of Perpendicular dropped on AC
h 1 = 5 cm
& h 2 = 3 cm
Now,
Area of ABCD = d/2 (h 1 + h 2 )
= 10/2 (5 + 3)
= 10/2 × 8
= 5 × 8
= 40 cm 2
Area of quadrilateral =
40 cm
2