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Ex 11.1, 4 - A flooring tile has the shape of a parallelogram whose

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Question 4 A flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm. How many such tiles are required to cover a floor of area 1080 π‘š^2? (If required you can split the tiles in whatever way you want to fill up the corners). Given, Tile is in shape of parallelogram And, Base = 24 cm Height = 10 cm Now, Number of tiles required = (π΄π‘Ÿπ‘’π‘Ž π‘œπ‘“ π‘“π‘™π‘œπ‘œπ‘œπ‘Ÿ)/(π΄π‘Ÿπ‘’π‘Ž π‘œπ‘“ π‘œπ‘›π‘’ 𝑑𝑖𝑙𝑒) Given, Area of floor = 1080 m2 = 1080 Γ— (100)2 cm2 = 1080 Γ— 100 Γ— 100 cm2 = 1080 Γ— 10000 cm2 Now, finding area of tile Area of tile = Area of parallelogram = Base Γ— Height = 24 Γ— 10 = 240 cm2 Now, Number of tiles required = (π΄π‘Ÿπ‘’π‘Ž π‘œπ‘“ π‘“π‘™π‘œπ‘œπ‘œπ‘Ÿ)/(π΄π‘Ÿπ‘’π‘Ž π‘œπ‘“ π‘œπ‘›π‘’ 𝑑𝑖𝑙𝑒) = (1080 Γ— 10000 )/240 = (1080 Γ— 1000)/24 = (540 Γ— 1000)/12 = (90 Γ— 1000)/2 = 45 Γ— 1000 = 45000 ∴ 45000 tiles are required to cover the floor.

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.