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Ex 11.1, 4 - A flooring tile has the shape of a parallelogram whose

Ex 11.1, 4 - Chapter 11 Class 8 Mensuration - Part 2
Ex 11.1, 4 - Chapter 11 Class 8 Mensuration - Part 3

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Ex 11.1, 4 A flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm. How many such tiles are required to cover a floor of area 1080 π‘š^2? (If required you can split the tiles in whatever way you want to fill up the corners). Given, Tile is in shape of parallelogram And, Base = 24 cm Height = 10 cm Now, Number of tiles required = (π΄π‘Ÿπ‘’π‘Ž π‘œπ‘“ π‘“π‘™π‘œπ‘œπ‘œπ‘Ÿ)/(π΄π‘Ÿπ‘’π‘Ž π‘œπ‘“ π‘œπ‘›π‘’ 𝑑𝑖𝑙𝑒) Given, Area of floor = 1080 m2 = 1080 Γ— (100)2 cm2 = 1080 Γ— 100 Γ— 100 cm2 = 1080 Γ— 10000 cm2 Now, finding area of tile Area of tile = Area of parallelogram = Base Γ— Height = 24 Γ— 10 = 240 cm2 Now, Number of tiles required = (π΄π‘Ÿπ‘’π‘Ž π‘œπ‘“ π‘“π‘™π‘œπ‘œπ‘œπ‘Ÿ)/(π΄π‘Ÿπ‘’π‘Ž π‘œπ‘“ π‘œπ‘›π‘’ 𝑑𝑖𝑙𝑒) = (1080 Γ— 10000 )/240 = (1080 Γ— 1000)/24 = (540 Γ— 1000)/12 = (90 Γ— 1000)/2 = 45 Γ— 1000 = 45000 ∴ 45000 tiles are required to cover the floor.

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.