Ex 11.1, 2 - Mrs. Kaushik has a square plot with the measurement as

Ex 11.1, 2 - Chapter 11 Class 8 Mensuration - Part 2
Ex 11.1, 2 - Chapter 11 Class 8 Mensuration - Part 3

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Question 2 Mrs. Kaushik has a square plot with the measurement as shown in the figure. She wants to construct a house in the middle of the plot. A garden is developed around the house. Find the total cost of developing a garden around the house at the rate of Rs 55 per 𝑚^2. First we find area of garden Now, Area of garden = Area of square of side 25 cm − Area of rectangle of length 20 m & breadth 15 m Area of Square Area = (Side)2 Putting Side = 25 m Area = (25)2 = 25 × 25 = 625 m2 Area of rectangle Area = l × b Putting l = 20 m & b = 15 m Area = 20 × 15 = 300 m2 Now, Area of garden = Area of Square − Area of Rectangle = 625 m2 − 300 m2 = 325 m2 Given, Cost of developing 1 m2 garden = Rs 55 Cost of Developing 325 m2 garden = Rs 325 × 55 = Rs 17,875 ∴ Total Cost of Developing the garden = Rs 17,875

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.