Example 3 - Construct a quadrilateral MIST, MI = 3.5 cm, IS = 6.5 cm

Example 3 - Chapter 4 Class 8 Practical Geometry - Part 2
Example 3 - Chapter 4 Class 8 Practical Geometry - Part 3
Example 3 - Chapter 4 Class 8 Practical Geometry - Part 4
Example 3 - Chapter 4 Class 8 Practical Geometry - Part 5 Example 3 - Chapter 4 Class 8 Practical Geometry - Part 6 Example 3 - Chapter 4 Class 8 Practical Geometry - Part 7


Transcript

Example 3 Construct a quadrilateral MIST where MI = 3.5 cm, IS = 6.5 cm, ∠M = 75°, ∠I = 105° and ∠S = 120°. Here, we are given two adjacent sides, and 3 angles No diagonals are given Let’s draw a rough sketch Let’s construct it Here, we are given two adjacent sides, and 3 angles No diagonals are given Let’s draw a rough sketch Let’s construct it 2. Now, we draw 75° from point M Check Ex 11.1, 4 (i) of Chapter 11 Class 9 NCERT to see how to draw 75° 3. We draw 105° from point I Check Ex 11.1, 4 (ii) of Chapter 11 Class 9 NCERT to see how to draw 105° Taking 6.5 cm as radius, and I as center, draw an arc. Where the arc intersects the line is point S 5. We draw 120° from point S Check Chapter 11 Class 9 NCERT to see how to draw 120° 6. Mark point T where the lines from point S and point M intersect Label the sides ∴ MIST is the required quadrilateral

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.