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Example 4 - Practical Geometry

Last updated at May 29, 2023 by

Example 4 - Construct a quadrilateral ABCD, where AB = 4 cm, BC = 5 cm

Example 4 - Chapter 4 Class 8 Practical Geometry - Part 2
Example 4 - Chapter 4 Class 8 Practical Geometry - Part 3 Example 4 - Chapter 4 Class 8 Practical Geometry - Part 4 Example 4 - Chapter 4 Class 8 Practical Geometry - Part 5 Example 4 - Chapter 4 Class 8 Practical Geometry - Part 6

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Example 4 Construct a quadrilateral ABCD, where AB = 4 cm, BC = 5 cm, CD = 6.5 cm and ∠B = 105° and ∠C = 80°. Here, we are given 3 adjacent sides, and 2 angles No diagonals are given Let’s draw a rough sketch Let’s construct it Steps of construction 1. Draw side BC of length 5 cm 2. We draw 105° from point B Check Ex 11.1, 4 (ii) of Chapter 11 Class 9 NCERT to see how to draw 105° 3. We draw 80° from point C 4. Taking 4 cm as radius, and B as center. Draw an arc. Mark the point where arc and line intersect as A Taking 6.5 cm as radius, and C as center. Draw an arc. Mark the point where arc and line intersect as D 5. Join AD Label the sides

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.