# Example 2 - Chapter 4 Class 8 Practical Geometry

Last updated at Oct. 3, 2018 by Teachoo

Last updated at Oct. 3, 2018 by Teachoo

Transcript

Example 2 Construct a quadrilateral ABCD, given that BC = 4.5 cm, AD = 5.5 cm, CD = 5 cm the diagonal AC = 5.5 cm and diagonal BD = 7 cm. First we draw a rough sketch Let’s construct it Steps of construction 1. Draw diagonal AC of length 5.5 cm 2. First, we will mark point D Taking 5.5 cm as radius, and A as center, draw an arc on bottom of AC 3. Taking 5 cm as radius, and C as center, draw an arc on bottom of AC Mark point D as the point where two arcs intersect at bottom of AC Mark point D as the point where two arcs intersect at bottom of AC 6. Taking 7 cm as radius, and D as center, draw an arc on top of AC 7. Mark point B as the point where two arcs intersect at top of AC Join AB, BC, AD, CD, BD Label the sides

Constructing Quadrilateral - 2 Diagnols and 3 sides given

Chapter 4 Class 8 Practical Geometry

Concept wise

- Basics
- Constructing a Quadrilateral
- Constructing Quadrilateral - 4 sides and diagonal given
- Constructing Quadrilateral - 2 Diagnols and 3 sides given
- Constructing Quadrilateral - 2 Adjacent Sides and 3 angles given
- Constructing Quadrilateral - 3 Sides and 2 angles given
- Constructing Square
- Constructing Rectangle
- Constructing Parallelogram
- Constructing Rhombus

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.