Example 2 - Chapter 4 Class 8 Practical Geometry
Last updated at Oct. 3, 2018 by Teachoo
Last updated at Oct. 3, 2018 by Teachoo
Transcript
Example 2 Construct a quadrilateral ABCD, given that BC = 4.5 cm, AD = 5.5 cm, CD = 5 cm the diagonal AC = 5.5 cm and diagonal BD = 7 cm. First we draw a rough sketch Let’s construct it Steps of construction 1. Draw diagonal AC of length 5.5 cm 2. First, we will mark point D Taking 5.5 cm as radius, and A as center, draw an arc on bottom of AC 3. Taking 5 cm as radius, and C as center, draw an arc on bottom of AC Mark point D as the point where two arcs intersect at bottom of AC Mark point D as the point where two arcs intersect at bottom of AC 6. Taking 7 cm as radius, and D as center, draw an arc on top of AC 7. Mark point B as the point where two arcs intersect at top of AC Join AB, BC, AD, CD, BD Label the sides
Constructing Quadrilateral - 2 Diagnols and 3 sides given
Constructing Quadrilateral - 2 Diagnols and 3 sides given
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