Ex 4.2, 1 (i) - Construct Quadrilateral LIFT, LI =  4 cm, IF = 3 cm

Ex 4.2, 1 (i) - Chapter 4 Class 8 Practical Geometry - Part 2
Ex 4.2, 1 (i) - Chapter 4 Class 8 Practical Geometry - Part 3
Ex 4.2, 1 (i) - Chapter 4 Class 8 Practical Geometry - Part 4
Ex 4.2, 1 (i) - Chapter 4 Class 8 Practical Geometry - Part 5
Ex 4.2, 1 (i) - Chapter 4 Class 8 Practical Geometry - Part 6
Ex 4.2, 1 (i) - Chapter 4 Class 8 Practical Geometry - Part 7
Ex 4.2, 1 (i) - Chapter 4 Class 8 Practical Geometry - Part 8

  1. Chapter 4 Class 8 Practical Geometry
  2. Concept wise

Transcript

Ex 4.2, 1 (i) Construct the following quadrilaterals. Quadrilateral LIFT LI = 4 cm IF = 3 cm TL = 2.5 cm LF = 4.5 cm IT = 4 cm First we draw a rough sketch Let’s construct it Steps of construction 1. Draw diagonal LF of length 4.5 cm Steps of construction 1. Draw diagonal LF of length 4.5 cm 3. Taking 3 cm as radius, and F as center, draw an arc on top of LF 4. Mark point I as the point where two arcs intersect at top of LF 5. Now, we will mark point T Taking 2.5 cm as radius, and L as center, draw an arc on bottom of LF 6. Taking 4 cm as radius, and I as center, draw an arc on bottom of LF 7. Mark point T as the point where two arcs intersect at bottom of LF Join LI, IF, FT, LT, IT Label the sides ∴ LIFT is the required quadrilateral

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.