Check sibling questions

Example 1 - Construct a quadrilateral PQRS where PQ = 4 cm, QR = 6 cm

Example 1 - Chapter 4 Class 8 Practical Geometry - Part 2
Example 1 - Chapter 4 Class 8 Practical Geometry - Part 3
Example 1 - Chapter 4 Class 8 Practical Geometry - Part 4
Example 1 - Chapter 4 Class 8 Practical Geometry - Part 5
Example 1 - Chapter 4 Class 8 Practical Geometry - Part 6
Example 1 - Chapter 4 Class 8 Practical Geometry - Part 7

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Transcript

Example 1 Construct a quadrilateral PQRS where PQ = 4 cm, QR = 6 cm, RS = 5 cm, PS = 5.5 cm and PR = 7 cm. First we draw a rough sketch Let’s construct it Steps of construction 1. Draw diagonal PR of length 7 cm 2. Taking 4 cm as radius, and P as center, draw an arc on top of PR 3. Taking 6 cm as radius, and R as center, draw an arc on top of PR 4. Taking 5.5 cm as radius, and P as center, draw an arc below of PR 5. Taking 5 cm as radius, and R as center, draw an arc below of PR 6. Let Q be the point where arcs intersect on top of PR, and S be the point where arcs intersect below PR Join PQ, PR, PS, SR Label the sides ∴ PQRS is the required quadrilateral

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.