Ex 11.2, 5
Construct a Right triangle whose base is 12 cm and sum of its hypotenuse and other side is 18 cm.
Let Δ ABC be the right angled triangle
where BC = 12 cm,
∠ B = 90° and
AC + AB = 18 cm
Steps of Construction:
Draw base BC of length 12 cm
2. Now, let’s draw ∠ B = 90°
Let the ray be BX
Check Ex 11.1, 1
on how to construct 90°
3. Open the compass to length AB + AC = 18 cm.
From point B as center, cut an arc on ray BX.
Let the arc intersect BX at D
4. Join CD
Now, we will draw perpendicular bisector of CD
6. Mark point A where perpendicular bisector intersects BD
Join AC
∴ Δ ABC is the required triangle

Made by

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.