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  1. Chapter 11 Class 9 Constructions
  2. Serial order wise
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Construct a triangle ABC, in which B = 60 , C = 45 and AB + BC + CA = 11 cm Steps of Construction: 1.Draw a line segment PQ equal to AB + BC + CA = 11 cm. Make LPQ = B = 60 and MQP= C = 45 Bisect LPQ and MQP. Let these bisectors intersect at a point A . Draw perpendicular bisectors of line AP and AQ Let XY intersect PQ at B and RS intersect PQ at C. Join AB and AC Thus, ABC is a the required triangle

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.