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Last updated at Oct. 5, 2018 by Teachoo

Transcript

Example 1 Construct a triangle ABC, in which ∠B = 60°, ∠C = 45° and AB + BC + CA = 11 cm Given ∠B = 60°, ∠C = 45° and AB + BC + CA = 11 cm Let’s construct Δ ABC Steps of Construction : Draw a line segment XY equal to AB + AC + BC = 11 cm. Make angle equal to ∠ B = 60° from point X Let the angle be ∠ LXY. Make angle equal to ∠C = 45° from point Y Let the angle be ∠ MYX 4. Bisect ∠ LXY and ∠ MYX. Let these bisectors intersect at a point A . 5. Make perpendicular bisector of AX Let it intersect XY at point B 6. Make perpendicular bisector of AY Let it intersect XY at point C 7. Join AB & AC ∴ Δ ABC is the required triangle

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.