Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class

Examples

Example 1
Important
Deleted for CBSE Board 2024 Exams

Construction 11.1 Deleted for CBSE Board 2024 Exams You are here

Construction 11.2 Important Deleted for CBSE Board 2024 Exams

Construction 11.3 Deleted for CBSE Board 2024 Exams

Construction 11.4 Deleted for CBSE Board 2024 Exams

Construction 11.5 Important Deleted for CBSE Board 2024 Exams

Construction 11.6 Important Deleted for CBSE Board 2024 Exams

Constructions

Serial order wise

Last updated at May 29, 2023 by Teachoo

Construction 11.1 : To construct the bisector of a given angle. Given an angle ABC, we want to construct is bisector Steps of Construction: 1. Draw an arc of any radius intersecting BA and BC at points E & D 2. Next, taking D and E as centers and with the radius more than 1/2 DE, draw arcs to intersect each other. 3. Mark the point as F. 4. Join BF So, BF is the bisector of the ∠ ABC. Justification We have to prove BF bisects ∠ ABC, i.e. we have to prove ∠ EBF = ∠ DBF Join DF and EF. In Δ BEF and Δ BDF, BE = BD EF = DF BF = BF ∴ ∆BEF ≅ ∆BDF ∴ ∠ EBF = ∠ DBF Thus, BF is bisector of ∠ ABC (Radii of the same arc) (Arcs of equal radii) (Common) (SSS Rule) (CPCT) (CPCT)