Constructions
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Ex 11.2, 1 - Construct triangle - BC = 7cm, B = 75, AB + AC = 13 cm

Ex 11.2, 1 - Chapter 11 Class 9 Constructions - Part 2
Ex 11.2, 1 - Chapter 11 Class 9 Constructions - Part 3

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Transcript

Question 1 Construct a triangle ABC in which BC = 7 cm, ∠B = 75° and AB + AC = 13 cm. Steps of Construction: Draw base BC of length 7 cm 2. Now, let’s draw ∠ B = 75° Let the ray be BX Check Ex 11.1, 4 (i) on how to construct 75° 3. Open the compass to length AB + AC = 13 cm. From point B as center, cut an arc on ray BX. Let the arc intersect BX at D 4. Join CD Now, we will draw perpendicular bisector of CD 6. Mark point A where perpendicular bisector intersects BD Join AC ∴ Δ ABC is the required triangle Now, we will draw perpendicular bisector of CD 6. Mark point A where perpendicular bisector intersects BD Join AC ∴ Δ ABC is the required triangle

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.