Ex 11.2, 3
Construct a triangle PQR in which QR = 6 cm, ∠Q = 60° and PR − PQ = 2 cm.
Steps of Construction:
Draw base QR of length 6 cm
2. Now, let’s draw ∠ Q = 60°
Let the ray be QX
Open the compass to length PR – PQ = 2 cm.
From point Q as center, cut an arc on ray QX. (opposite side of QR).
Let the arc intersect QX at D
4. Join RD
Note: Since PR – PQ = 2 cm,
(PQ – PR) is negative So, QD will be below line QR
Now, we will draw perpendicular bisector of RD
6. Mark point P where perpendicular bisector intersects RD
Join PR
∴ Δ PQR is the required triangle

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.

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