Last updated at May 29, 2018 by Teachoo
Ex 11.2, 3
Construct a triangle PQR in which QR = 6 cm, ∠Q = 60° and PR − PQ = 2 cm.
Given that, In ∆PQR, QR = 6 cm, ∠Q = 60° and PR − PQ = 2 cm.
Steps of Construction
Cut a line segment QD equal to PR – PQ from ray BX
Join DR. Draw perpendicular bisector
AB of line DR.
Let AB intersect QX a point P.
Join PR.
∴ Δ PQR is the required triangle
Transcript
Ex 11.2, 3 Construct a triangle PQR in which QR = 6 cm, ∠Q = 60° and PR − PQ = 2 cm. Given that, In ∆PQR, QR = 6 cm, ∠Q = 60° and PR − PQ = 2 cm. Steps of Construction Draw base QR = 6 cm and at point B make a ∠ XQR = ∠ Q = 60° Cut a line segment QD equal to PR – PQ from ray BX Join DR. Draw perpendicular bisector AB of line DR. Let AB intersect QX a point P. Join PR. ∴ Δ PQR is the required triangle
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