![Ex 11.2, 2 - Chapter 11 Class 9 Constructions - Part 2](https://d1avenlh0i1xmr.cloudfront.net/8f8cca25-1618-45d7-94d6-5634cf3ab27e/slide5.jpg)
![Ex 11.2, 2 - Chapter 11 Class 9 Constructions - Part 3](https://d1avenlh0i1xmr.cloudfront.net/1b62f353-f8e2-4349-8516-119e47cedd22/slide6.jpg)
Constructing Triangle (with different criterias)
Constructing Triangle (with different criterias)
Last updated at April 16, 2024 by Teachoo
Question 2 Construct a triangle ABC in which BC = 8 cm, ∠B = 45° and AB − AC = 3.5 cm. Steps of Construction: Draw base BC of length 8 cm 2. Now, let’s draw ∠ B = 45° Let the ray be BX Check Ex 11.1, 2 on how to construct 45° Open the compass to length AB – AC = 3.5 cm. From point B as center, cut an arc on ray BX. Let the arc intersect BX at D 4. Join CD Note: Since AB – AC = 3.5 cm is positive So, BD will be above line BC Now, we will draw perpendicular bisector of CD 6. Mark point A where perpendicular bisector intersects BD Join AC ∴ Δ ABC is the required triangle