Ex 11.2, 2 - Construct triangle ABC - BC = 8cm, B = 45, AB - AC = 3.5

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Ex 11.2, 2 - Chapter 11 Class 9 Constructions - Part 2

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Ex 11.2, 2 - Chapter 11 Class 9 Constructions - Part 3

  1. Chapter 11 Class 9 Constructions (Term 2)
  2. Serial order wise

Transcript

Ex 11.2, 2 Construct a triangle ABC in which BC = 8 cm, ∠B = 45° and AB − AC = 3.5 cm. Steps of Construction: Draw base BC of length 8 cm 2. Now, let’s draw ∠ B = 45° Let the ray be BX Check Ex 11.1, 2 on how to construct 45° Open the compass to length AB – AC = 3.5 cm. From point B as center, cut an arc on ray BX. Let the arc intersect BX at D 4. Join CD Note: Since AB – AC = 3.5 cm is positive So, BD will be above line BC Now, we will draw perpendicular bisector of CD 6. Mark point A where perpendicular bisector intersects BD Join AC ∴ Δ ABC is the required triangle

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.