Constructions
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Ex 11.2, 4 - Construct triangle XYZ - angle Y = 30, Z = 90, XY + YZ+ZX

Ex 11.2, 4 - Chapter 11 Class 9 Constructions - Part 2
Ex 11.2, 4 - Chapter 11 Class 9 Constructions - Part 3 Ex 11.2, 4 - Chapter 11 Class 9 Constructions - Part 4 Ex 11.2, 4 - Chapter 11 Class 9 Constructions - Part 5

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Transcript

Question 4 Construct a triangle ∆XYZ in which ∠Y = 30°, ∠Z = 90° and XY + YZ + ZX = 11 cm. Given ∠Y = 30°, ∠Z = 90° and XY + YZ + ZX = 11 cm. Let’s construct Δ XYZ Steps of Construction : Draw a line segment AB equal to XY + YZ + ZX = 11 cm. Make angle equal to ∠ Y = 30° from point A Let the angle be ∠ LAB. Make angle equal to ∠Z = 90° from point B Let the angle be ∠ MBA 4. Bisect ∠ LAB and ∠ MBA. Let these bisectors intersect at a point X . 5. Make perpendicular bisector of XA Let it intersect AB at point Y 6. Make perpendicular bisector of XB Let it intersect AB at point Z 7. Join XY & XZ ∴ Δ XYZ is the required triangle

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.