Ex 11.2, 4
Construct a triangle ∆XYZ in which ∠Y = 30°, ∠Z = 90° and XY + YZ + ZX = 11 cm.
Given ∠Y = 30°, ∠Z = 90° and XY + YZ + ZX = 11 cm.
Let’s construct Δ XYZ
Steps of Construction :
Draw a line segment AB equal to XY + YZ + ZX = 11 cm.
Make angle equal to ∠ Y = 30° from point A
Let the angle be ∠ LAB.
Make angle equal to ∠Z = 90° from point B
Let the angle be ∠ MBA
4. Bisect ∠ LAB and ∠ MBA.
Let these bisectors intersect at a point X .
5. Make perpendicular bisector of XA
Let it intersect AB at point Y
6. Make perpendicular bisector of XB
Let it intersect AB at point Z
7. Join XY & XZ
∴ Δ XYZ is the required triangle

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.

Hi, it looks like you're using AdBlock :(

Displaying ads are our only source of revenue. To help Teachoo create more content, and view the ad-free version of Teachooo... please purchase Teachoo Black subscription.

Please login to view more pages. It's free :)

Teachoo gives you a better experience when you're logged in. Please login :)

Solve all your doubts with Teachoo Black!

Teachoo answers all your questions if you are a Black user!