Ex 11.2, 4
Construct a triangle ∆XYZ in which ∠Y = 30°, ∠Z = 90° and XY + YZ + ZX = 11 cm.
Given ∠Y = 30°, ∠Z = 90° and XY + YZ + ZX = 11 cm.
Let’s construct Δ XYZ
Steps of Construction :
Draw a line segment AB equal to XY + YZ + ZX = 11 cm.
Make angle equal to ∠ Y = 30° from point A
Let the angle be ∠ LAB.
Make angle equal to ∠Z = 90° from point B
Let the angle be ∠ MBA
4. Bisect ∠ LAB and ∠ MBA.
Let these bisectors intersect at a point X .
5. Make perpendicular bisector of XA
Let it intersect AB at point Y
6. Make perpendicular bisector of XB
Let it intersect AB at point Z
7. Join XY & XZ
∴ Δ XYZ is the required triangle

Made by

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.