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Ex 11.2, 4 - Construct triangle XYZ - angle Y = 30, Z = 90, XY + YZ+ZX

Ex 11.2, 4 - Chapter 11 Class 9 Constructions - Part 2
Ex 11.2, 4 - Chapter 11 Class 9 Constructions - Part 3 Ex 11.2, 4 - Chapter 11 Class 9 Constructions - Part 4 Ex 11.2, 4 - Chapter 11 Class 9 Constructions - Part 5

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Ex 11.2, 4 Construct a triangle ∆XYZ in which ∠Y = 30°, ∠Z = 90° and XY + YZ + ZX = 11 cm. Given ∠Y = 30°, ∠Z = 90° and XY + YZ + ZX = 11 cm. Let’s construct Δ XYZ Steps of Construction : Draw a line segment AB equal to XY + YZ + ZX = 11 cm. Make angle equal to ∠ Y = 30° from point A Let the angle be ∠ LAB. Make angle equal to ∠Z = 90° from point B Let the angle be ∠ MBA 4. Bisect ∠ LAB and ∠ MBA. Let these bisectors intersect at a point X . 5. Make perpendicular bisector of XA Let it intersect AB at point Y 6. Make perpendicular bisector of XB Let it intersect AB at point Z 7. Join XY & XZ ∴ Δ XYZ is the required triangle

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