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Construction 11.1 Deleted for CBSE Board 2025 Exams
Construction 11.2 Important Deleted for CBSE Board 2025 Exams
Construction 11.3 Deleted for CBSE Board 2025 Exams You are here
Construction 11.4 Deleted for CBSE Board 2025 Exams
Construction 11.5 Important Deleted for CBSE Board 2025 Exams
Construction 11.6 Important Deleted for CBSE Board 2025 Exams
Last updated at April 16, 2024 by Teachoo
Construction 11.3 : To construct an angle of 60° at the initial point of a given ray. Steps of Construction : Draw a ray AB with initial point A 2. Taking A as centre and some radius, draw an arc, which intersects AB at Point D. Construction 11.3 : To construct an angle of 60° at the initial point of a given ray. Steps of Construction : Draw a ray AB with initial point A 2. Taking A as centre and some radius, draw an arc, which intersects AB at Point D. 3. Taking D as Centre and with the same radius as before, draw an arc intersecting the previously drawn arc at point E. 4. Draw the ray AC Passing through E. Thus, ∠CAB = 60° Justification We need to prove ∠ CAB = 60° Join DE. Since Arc AD = Arc AE and using same radius, we drew arc DE Thus, their radius will be the same ∴ AE = AD = DE Therefore, ∆ EAD is an equilateral triangle ∴ ∠EAD = 60° ⇒ ∠CAB = 60°. Hence justified (Radius of equal arcs - By Construction) (All angles of equilateral triangle are 60°)