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Ex 11.2, 4

Construct a triangle ∆XYZ in which ∠Y = 30° ∠Z = 90° and XY + YZ + ZX = 11 cm.

Steps of Construction:

  1. Draw a line segment PQ equal to XY + YZ + ZX = 11 cm.
  2. Make ∠ LPQ = ∠Y = 30° and ∠ MQP = ∠Z = 90°
  3. Bisect ∠ LPQ and ∠ MQP. Let these bisectors intersect at a point X .
  4. Draw perpendicular bisectors of line XP and XQ
  5. Let AB intersect PQ at Y and CD intersect PQ at Z.
  6. Join XY and XZ

∴ Δ XYZ is the required triangle


  1. Chapter 11 Class 9 Constructions
  2. Serial order wise
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Transcript

Ex 11.2, 4 Construct a triangle ∆XYZ in which ∠Y = 30° ∠Z = 90° and XY + YZ + ZX = 11 cm. Steps of Construction: Draw a line segment PQ equal to XY + YZ + ZX = 11 cm. Make ∠ LPQ = ∠Y = 30° and ∠ MQP = ∠Z = 90° Bisect ∠ LPQ and ∠ MQP. Let these bisectors intersect at a point X . Draw perpendicular bisectors of line XP and XQ Let AB intersect PQ at Y and CD intersect PQ at Z. Join XY and XZ ∴ Δ XYZ is the required triangle

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He provides courses for Mathematics from Class 9 to 12. You can ask questions here.
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