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Ex 11.2, 1

Construct a triangle ABC in which BC = 7 cm, ∠B = 75°  and AB + AC = 13 cm.

Steps of Construction :

  1. Draw base BC  = 7 cm and at point B make an ∠ XBC = ∠ B = 75°
  2. Cut a line segment BD equal to AB + AC from ray BX.
  3. Join DC. Draw perpendicular bisector PQ of line DC.
  4. 4.Let PQ intersect BD a point A. Join AC.

Then, Δ ABC is the required triangle.

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  1. Chapter 11 Class 9 Constructions
  2. Serial order wise
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CA Maninder Singh
CA Maninder Singh is a Chartered Accountant for the past 6 years. He provides courses for Practical Accounts, Taxation and Efiling at teachoo.com .
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