Ex 11.2, 1
Construct a triangle ABC in which BC = 7 cm, ∠B = 75° and AB + AC = 13 cm.
Steps of Construction :
- Draw base BC = 7 cm and at point B make an ∠ XBC = ∠ B = 75°
- Cut a line segment BD equal to AB + AC from ray BX.
- Join DC. Draw perpendicular bisector PQ of line DC.
- 4.Let PQ intersect BD a point A. Join AC.
Then, Δ ABC is the required triangle.