1. Chapter 11 Class 9 Constructions
  2. Serial order wise
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Ex 11.2, 1 Construct a triangle ABC in which BC = 7 cm, ∠B = 75°  and AB + AC = 13 cm. Steps of Construction: Draw base BC  = 7 cm and at point B make an ∠ XBC = ∠ B = 75° Cut a line segment BD equal to AB + AC from ray BX. Join DC. Draw perpendicular bisector PQ of line DC. 4.Let PQ intersect BD a point A. Join AC. Then, Δ ABC is the required triangle.

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