# Misc 10

Last updated at May 29, 2018 by Teachoo

Last updated at May 29, 2018 by Teachoo

Transcript

Misc 10 A toy company manufactures two types of dolls, A and B. Market tests and available resources have indicated that the combined production level should not exceed 1200 dolls per week and the demand for dolls of type B is at most half of that for dolls of type A. Further, the production level of dolls of type A can exceed three times the production of dolls of other type by at most 600 units. If the company makes profit of Rs 12 and Rs 16 per doll respectively on dolls A and B, how many of each should be produced weekly in order to maximise the profit? Let the number of dolls of type A be x & the number of dolls of type B be y According to Question Since combined production level should not exceed 1200 dolls ∴ x + y ≤ 1200 Also, production level of dolls of type A exceeds 3 times the production of type B by atmost 600. ∴ x - 3y ≤ 600 And, Demand of dolls of type is at most half of that of type A ∴ y ≤ 𝑥2 ⇒ 2y – x ≤ 0 We need to Maximize the profit Here, Profit on Type A dolls = Rs 12 Profit on Types B dolls = Rs 6 ∴ Maximize Z = 12x + 6y Combining all the constraints, Maximize Z = 12x + 6y Subject to constraints, x + y ≤ 1200 x – 3y ≤ 600 2y – x ≤ 0 & x ≥ 0, y ≥ 0 Hence, the Profit will be maximum if, the company Produces. Type A dolls = 800 Type B dolls = 400 & Max. Profit = Rs 16000

Class 12

Important Question for exams Class 12

- Chapter 1 Class 12 Relation and Functions
- Chapter 2 Class 12 Inverse Trigonometric Functions
- Chapter 3 Class 12 Matrices
- Chapter 4 Class 12 Determinants
- Chapter 5 Class 12 Continuity and Differentiability
- Chapter 6 Class 12 Application of Derivatives
- Chapter 7 Class 12 Integrals
- Chapter 8 Class 12 Application of Integrals
- Chapter 9 Class 12 Differential Equations
- Chapter 10 Class 12 Vector Algebra
- Chapter 11 Class 12 Three Dimensional Geometry
- Chapter 12 Class 12 Linear Programming
- Chapter 13 Class 12 Probability

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.