# Misc 3

Last updated at May 29, 2018 by Teachoo

Last updated at May 29, 2018 by Teachoo

Transcript

Misc 3 A dietician wishes to mix together two kinds of food X and Y in such a way that the mixture contains at least 10 units of vitamin A, 12 units of vitamin B and 8 units of vitamin C. The vitamin contents of one kg food is given below: One kg of food X costs Rs 16 and one kg of food Y costs Rs 20. Find the least cost of the mixture which will produce the required diet? According to Question : As, we need to minimize the cost of mixture, we will use function: Minimize Z Now, Food X cost → Rs 16 Food Y Cost → Rs 20 ∴ Z = 16x + 20Y Combining all Constraints : Min Z = 16x + 20y Subject to Constraints, x + 2y ≥ 10 x + y ≥ 6 3x + y ≥ 8 x ≥ 0, y ≥ 0 As, the feasible region is unbounded Hence, 112 may or may not be the minimum value of Z. For This, we need to graph inequality : 16x + 20y < 112 ⇒ 4x + 5y < 28 Since, there is no point in Common Between the feasible region & inequality. Hence, minimum value of Z is 112. Thus, Cost of Mixture will be minimum if 2 packets of Food X & 4 Packets of Food Y are used. Minimum cost of mixture is Rs 112.

Class 12

Important Question for exams Class 12

- Chapter 1 Class 12 Relation and Functions
- Chapter 2 Class 12 Inverse Trigonometric Functions
- Chapter 3 Class 12 Matrices
- Chapter 4 Class 12 Determinants
- Chapter 5 Class 12 Continuity and Differentiability
- Chapter 6 Class 12 Application of Derivatives
- Chapter 7 Class 12 Integrals
- Chapter 8 Class 12 Application of Integrals
- Chapter 9 Class 12 Differential Equations
- Chapter 10 Class 12 Vector Algebra
- Chapter 11 Class 12 Three Dimensional Geometry
- Chapter 12 Class 12 Linear Programming
- Chapter 13 Class 12 Probability

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.