Ex 9.3, 14 - Chapter 9 Class 12 Differential Equations (Important Question)

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Ex 9.3, 14 - Find particular solution: dy/dx = y tan x, y = 1 - Ex 9.3

part 2 - Ex 9.3, 14 - Ex 9.3 - Serial order wise - Chapter 9 Class 12 Differential Equations

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Transcript

Ex 9.3, 14 For each of the differential equations in Exercises 11 to 14, find a particular solution satisfying the given condition : 𝑑𝑦/𝑑π‘₯=𝑦 tan⁑ π‘₯;𝑦=1 When π‘₯=0 𝑑𝑦/𝑑π‘₯=𝑦 tan⁑ x π’…π’š/π’š=γ€–π­πšπ§ 𝐱 𝐝𝐱〗⁑ Integrating both sides ∫1▒𝑑𝑦/𝑦 = ∫1β–’tan⁑〖π‘₯ 𝑑π‘₯γ€— log |π’š| = log |π¬πžπœβ‘π’™ |+π’π’π’ˆβ‘π’„ log |𝑦| = log (c sec x) y = c sec x (∡ log π‘Ž + log b = log π‘Žb) Put x = 0 and y = 1 1 = C Sec 0 1 = C Γ— 1 C = 1 Put value of C in (1) y = 1 Γ— sec x y = sec x

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