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Ex 6.3
Ex 6.3, 2 Deleted for CBSE Board 2023 Exams
Ex 6.3, 3 Deleted for CBSE Board 2023 Exams
Ex 6.3, 4 Important Deleted for CBSE Board 2023 Exams
Ex 6.3, 5 Deleted for CBSE Board 2023 Exams
Ex 6.3, 6 Important Deleted for CBSE Board 2023 Exams
Ex 6.3, 7 Important Deleted for CBSE Board 2023 Exams
Ex 6.3, 8 Important Deleted for CBSE Board 2023 Exams
Ex 6.3, 9 Deleted for CBSE Board 2023 Exams
Ex 6.3, 10 Important Deleted for CBSE Board 2023 Exams
Ex 6.3, 11 Important Deleted for CBSE Board 2023 Exams
Ex 6.3, 12 Important Deleted for CBSE Board 2023 Exams
Ex 6.3, 13 Deleted for CBSE Board 2023 Exams You are here
Ex 6.3, 14 Important Deleted for CBSE Board 2023 Exams
Ex 6.3, 15 Important Deleted for CBSE Board 2023 Exams
Ex 6.3
Last updated at March 29, 2023 by Teachoo
Ex6.3, 13 Solve the following system of inequalities graphically: 4x + 3y ≤ 60, y ≥ 2x, x ≥ 3, x, y ≥ 0 Now we solve 4x + 3y ≤ 60 Lets first draw graph of 4x + 3y = 60 Drawing graph Checking for (0,0) Putting x = 0, y = 0 4x + 3y ≤ 60 4(0) + 3(0) ≤ 60 0 ≤ 60 which is true Hence origin lies in plane 3x + 4y ≤ 60 So, we shade left side of line Now we solve y ≥ 2x Lets first draw graph of y = 2x Drawing graph Checking for (0,15) Putting x = 0, y = 15 y ≥ 2x 15 ≥ 2(0) 15 ≥ 0 which is true Hence (0, 15) lies in plane y ≥ 2x So, we shade left side of line Also, x ≥ 3 So, for all values of y, x = 3 Given x ≥ 3, so we shade right side of line Also, given x , y ≥ 0 So, the shaded region will line in 1st quadrant Hence the shaded region represents the given inequality