Example 1 - Chapter 6 Class 11 Linear Inequalities (Term 2)
Last updated at Jan. 12, 2022 by
Transcript
Example 1 Solve 30 x < 200 when (i) x is a natural number 30 x < 200 ๐ฅ < 200/30 ๐ฅ < 20/3 ๐ < 6.66 Since x is a natural number i.e. 1, 2, 3, 4, 5, 6, 7,โฆ. We need to find values of x which is less than or equal to 6 i.e. x can be {1, 2, 3, 4, 5, 6} Example 1 Solve 30 x < 200 when (ii) x is an integer Now, ๐ < 6.66 Since x is an integer i.e. โฆโฆ,โ3, โ2, โ1, 0, 1, 2, 3โฆ. We need to find values of x which is less than or equal 6 i.e. x can be โฆโฆ, โ3, โ2, โ1, 0, 1, 2, 3, 4, 5, 6 = {โฆโฆ,โ3, โ2, โ1, 0, 1, 2, 3, 4, 5, 6}
Solving inequality (one side)
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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.
