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  1. Chapter 6 Class 11 Linear Inequalities
  2. Concept wise


Example 4 Solve (5 โˆ’ 2๐‘ฅ)/3 โ‰ค ๐‘ฅ/6 โˆ’ 5. (5 โˆ’ 2๐‘ฅ)/3 โ‰ค ๐‘ฅ/6 โˆ’ 5 (5 โˆ’ 2๐‘ฅ)/3 โ‰ค (๐‘ฅ โˆ’ 30)/6 6 ร— (5 โˆ’ 2๐‘ฅ)/3 โ‰ค x โ€“ 30 2(5 โ€“ 2x) โ‰ค x โ€“ 30. 10 โ€“ 4x โ‰ค x โ€“ 30 โ€“ 4x โ€“ x โ‰ค โ€“ 30 โ€“ 10 โ€“ 5x โ‰ค โ€“ 40 โ€“ x โ‰ค (โˆ’40)/( 5) โ€“ x โ‰ค โˆ’8 Since x is negative, we multiply both sides by โˆ’1 & change the signs (โ€“ 1) ร— (โ€“x) โ‰ฅ (โ€“ 1) ร— (โ€“8) x โ‰ฅ 8 Hence, x is a real number greater than or equal to 8 Hence, x โˆˆ [8, โˆž) is the solution

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.