Check sibling questions

Ex 6.3, 2 - Chapter 6 Class 11 Linear Inequalities (Term 2)

Last updated at March 16, 2023 by

Ex 6.3, 2 - Solve 3x + 2y <= 12, x >= 1, y >= 2 graphically

Ex 6.3, 2 - Chapter 6 Class 11 Linear Inequalities - Part 2
Ex 6.3, 2 - Chapter 6 Class 11 Linear Inequalities - Part 3

Get live Maths 1-on-1 Classs - Class 6 to 12

Book 30 minute class for ₹ 499 ₹ 299

Transcript

Ex6.3, 2 Solve the following system of inequalities graphically: 3x + 2y 12, x 1, y 2 First we solve 3x + 2y 12 Lets first draw graph of 3x + 2y = 12 Drawing graph Checking for (0,0) Putting x = 0, y = 0 3x + 2y 12 3(0) + 2(0) 12 0 12 which is true Hence origin lies in plane 3x + 2y 12 So, we shade left side of line Also, y 2 So, for all values of x, y = 2 Also, x 1 So, for all values of y, x = 1 Hence the shaded region represents the given in equality

Ask a doubt
Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.