# E x6.3, 4

Last updated at Nov. 22, 2017 by Teachoo

Last updated at Nov. 22, 2017 by Teachoo

Transcript

Ex6.3, 4 Solve the following system of inequalities graphically: x + y ≥ 4, 2x – y < 0 First we solve x + y ≥ 4 Lets first draw graph of x + y = 3 Drawing graph Checking for (0,0) Putting x = 0, y = 0 x + y ≥ 4 0 + 0 ≥ 4 0 ≥ 5 which is false Hence origin does not lie in plane x + y ≥ 4 So, we shade the right side of line Now we solve 2x – y < 0 Lets first draw graph of 2x – y = 0 Drawing graph Checking for (4,0) Putting x = 4, y = 0 2x – y < 0 2(4) – 0 < 0 8 > 0 which is false Hence (4,0) does not lie in plane 2x – y > 0 So, we shade left side of line Hence the shaded region is the solution of the given inequality

Chapter 6 Class 11 Linear Inequalities

Serial order wise

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.