Ex 6.3, 9 - Solve 5x + 4y <= 20, x >= 1, y >= 2 - Class 11 - Graph - 2 or more Equation

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  1. Chapter 6 Class 11 Linear Inequalities
  2. Serial order wise
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Ex6.3, 9 Solve the following system of inequalities graphically: 5x + 4y 20, x 1, y 2 First we solve 5x + 4y 20 Lets first draw graph of 5x + 4y = 20 Drawing graph Checking for (0,0) 5x + 4y 20 Putting x = 0, y = 0 5(0) + 4(0) 20 0 20 which is true Hence origin lies in plane 5x + 4y 20 So, we shade left side of line Also, y 2 So, for all values of x, y = 2 Also, x 1 So, for all values of y, x = 1 Hence the shaded region represents the given in equality

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.