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  1. Chapter 13 Class 12 Probability
  2. Serial order wise

Transcript

Ex 13.3, 13 Probability that A speaks truth is 4/5 . A coin is tossed. A reports that a head appears. The probability that actually there was head is (A) 4/5 (B) 1/2 (C) 1/5 (D) 𝟐/πŸ“Let E : A speaks truth F : A Lies H : head appears on the toss of a coin We need to find the Probability that head actually appears, if A reports that a head appears i.e. P(E|H) P(E|H) = "P(E) . P(H|E) " /"P(F) . P(H|F) + P(E) . P(H|E)" P(E) = Probability that A speaks truth = 4/5 P(H|E) = Probability that head appears, if A speaks truth = 1/2 P(F) = Probability that A lies = 1 – P(E) = 1 – 4/5 = 1/5 P(H|F) = Probability that head appears, if A lies = 1/2 Putting values in formula, P(E|H) = (4/5 Γ— 1/2)/(1/5 Γ— 1/2 + 4/5 Γ— 1/2) = (1/5 Γ— 1/2 Γ— 4)/(1/5 Γ— 1/2 [1 + 4]) = 4/5 Putting values in formula, P(E|H) = (4/5 Γ— 1/2)/(1/5 Γ— 1/2 + 4/5 Γ— 1/2) = (1/5 Γ— 1/2 Γ— 4)/(1/5 Γ— 1/2 [1 + 4]) = 4/5 Therefore, required probability is 4/5 ∴ A is the correct answer

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.