Ex 13.3, 12

Transcript

Ex 13.3, 12 A card from a pack of 52 cards is lost. From the remaining cards of the pack, two cards are drawn and are found to be both diamonds. Find the probability of the lost card being a diamond. Let, E1 : Event that lost card is diamond E2 : Event that lost card is not a diamond A : Event that two cards drawn are diamond We need to find out that probability that the lost card being a diamond if two cards drawn are found to be both diamond. i.e. P(E1|A) P(E1|A) = 𝑃 𝐸﷮1﷯﷯.𝑃(𝐴| 𝐸﷮1﷯)﷮𝑃 𝐸﷮1﷯﷯.𝑃(𝐴| 𝐸﷮1﷯)+𝑃 𝐸﷮2﷯﷯.𝑃(𝐴| 𝐸﷮2﷯) ﷯ . Putting value in the formula, P(E1|A) = 𝑃 𝐸﷮1﷯﷯.𝑃(𝐴| 𝐸﷮1﷯)﷮𝑃 𝐸﷮1﷯﷯.𝑃(𝐴| 𝐸﷮1﷯)+𝑃 𝐸﷮2﷯﷯.𝑃(𝐴| 𝐸﷮2﷯) ﷯ = 1﷮4﷯ × 12 × 11﷮51 × 50﷯﷮ 1﷮4﷯ × 12 × 11﷮51 × 50﷯ + 3﷮4﷯ × 12 × 12﷮51 × 50﷯ ﷯ = 1﷮4﷯ × 12 ﷮51 × 50﷯ 11﷯﷮ 1﷮4﷯ × 12﷮51 × 50﷯ 11+ 3 × 13﷯ ﷯ = 11﷮11 + 39﷯ = 𝟏𝟏﷮𝟓𝟎﷯ Therefore, required probability is 11﷮50﷯