Question 14 (a) - Chapter 11 Class 12 Three Dimensional Geometry (Important Question)

Last updated at December 16, 2024 by

Ex 11.3, 14 (a) - Find distance of (0, 0, 0) from plane 3x-4y+12z=3

Ex 11.3, 14 (a) - Chapter 11 Class 12 Three Dimensional Geometry - Part 2

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Question 14 In the following cases, find the distance of each of the given points from the corresponding given plane. The distance of the point (x1, y1, z1) from the plane Ax + By + Cz = D is |(š‘Øš’™_šŸ + 怖š‘©š’šć€—_šŸ +怖 š‘Ŗš’›ć€—_šŸ āˆ’ š‘«)/āˆš(š‘Ø^šŸ + š‘©^šŸ + š‘Ŗ^šŸ )| Given, the point is (0, 0, 0) So, š‘„_1 = 0, š‘¦_1 = 0, š‘§_1 = 0 and the equation of plane is 3x āˆ’ 4y + 12z = 3 Comparing with Ax + By + Cz = D, A = 3, B = āˆ’4, C = 12, D = 3 Now, Distance of point from the plane is = |((3 Ɨ 0) + (āˆ’4 Ɨ 0) + (12 Ɨ 0) āˆ’ 3)/( āˆš(3^2 + (āˆ’4)^2 + 怖12怗^2 ))| = |(0 + 0 + 0 āˆ’ 3)/( āˆš(9 + 16 + 144))| = |3/( āˆš169)| = šŸ‘/šŸšŸ‘

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