Last updated at May 29, 2018 by Teachoo

Transcript

Ex 11.2, 5 Find the equation of the line in vector and in cartesian form that passes through the point with position vector 2 + 4 and is in the direction + 2 . Equation of a line passing though a point with position vector and parallel to vector is = + Here, = 2 + 4 & = + 2 So, = (2 + 4 ) + ( + 2 ) Equation of line in vector form is (2 + 4 ) + ( + 2 ) Equation of a line passing though (x1, y1, z1) and parallel to a line having direction ratios a, b, c is 1 = 1 = 1 Since the line passes through a point with position vector 2 + 4 , 1 = 2, y1 = 1 z1 = 4 Also, line is in the direction of + 2 , Direction ratios : = 1, b = 2 , c = 1 Equation of line in Cartesian form is 2 1 = ( 1) 2 = 4 1 = + =

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Ex 11.2, 5 Important You are here

Ex 11.2, 11 Important

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Ex 11.3, 4 Important

Ex 11.3, 11 Important

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Example 30 Important

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Class 12

Important Question for exams Class 12

- Chapter 1 Class 12 Relation and Functions
- Chapter 2 Class 12 Inverse Trigonometric Functions
- Chapter 3 Class 12 Matrices
- Chapter 4 Class 12 Determinants
- Chapter 5 Class 12 Continuity and Differentiability
- Chapter 6 Class 12 Application of Derivatives
- Chapter 7 Class 12 Integrals
- Chapter 8 Class 12 Application of Integrals
- Chapter 9 Class 12 Differential Equations
- Chapter 10 Class 12 Vector Algebra
- Chapter 11 Class 12 Three Dimensional Geometry
- Chapter 12 Class 12 Linear Programming
- Chapter 13 Class 12 Probability

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.