Vector product - Defination

Chapter 10 Class 12 Vector Algebra
Concept wise

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Example 22 Find |π β Γ π β|, if π β = 2π Μ + π Μ + 3π Μ and π β = 3π Μ + 5π Μ β 2π Μ Given π β = 2π Μ + π Μ + 3π Μ π β = 3π Μ + 5π Μ β 2π Μ Now, π β Γ π β = |β 8(π Μ&π Μ&π Μ@2&1&3@3&5&β2)| = π Μ (1 Γ (-2) β 5 Γ 3) β π Μ (2 Γ (-2) β 3 Γ 3) + π Μ (2 Γ 5 β 3 Γ 1) = π Μ (β2 β15) β π Μ (β4 β9) + π Μ (10 β 3) = β17π Μ + 13π Μ + 7π Μ So, Magnitude of π β Γ π β = β((β17)2+(13)2+(7)2) |π β" Γ " π β | = β(289+169+49) = β507 Thus, |π β" Γ " π β | = βπππ

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