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Vector product - Solving
Last updated at April 22, 2021 by Teachoo
Ex 10.4, 4 Show that (π β β π β) Γ (π β + π β) = 2(π β Γ π β) Solving L.H.S (π β β π β) Γ (π β + π β) = π β Γ (π β + π β) β π β Γ (π β + π β) = π β Γ π β + π β Γ π β β π β Γ π β β π β Γ π β = π β Γ π β + π β Γ π β β (β π β Γ π β) β π β Γ π β = π β Γ π β + π β Γ π β + π β Γ π β β π β Γ π β = π β Γ π β + 2(π β Γ π β) β π β Γ π β π β Γ π β = |π β ||π β | sin ΞΈ π Μ = |π β |2 sin 0 π Μ = 0 So, π β Γ π β = 0 Similarly, π β Γ π β = 0 = 0 + 2(π β Γ π β) β 0 = 2 (π β Γ π β) = RHS Since LHS = RHS, Hence proved.