Ex 10.2, 15 - Find position vector of a point R divides line

Ex 10.2, 15 - Chapter 10 Class 12 Vector Algebra - Part 2

Ex 10.2, 15 - Chapter 10 Class 12 Vector Algebra - Part 3

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Ex 10.2, 15 Find the position vector of a point R which divides the line joining two points P and Q whose position vectors are š‘– Ģ‚ + 2š‘— Ģ‚ āˆ’ š‘˜ Ģ‚ and – š‘– Ģ‚ + š‘— Ģ‚ + š‘˜ Ģ‚ respectively, in the ratio 2 : 1 (i) internally (š‘‚š‘ƒ) āƒ—= š‘– Ģ‚ + 2š‘— Ģ‚ āˆ’ š‘˜ Ģ‚ (š‘‚š‘„) āƒ—= – š‘– Ģ‚ + š‘— Ģ‚ + š‘˜ Ģ‚ Position vector of R = (2.(š‘‚š‘„) āƒ— + 1.(š‘‚š‘ƒ) āƒ—)/(2 + 1) (š‘‚š‘…) āƒ— = (2(āˆ’š‘– Ģ‚" + " š‘— Ģ‚" + " š‘˜ Ģ‚ ) + 1(š‘– Ģ‚" +" 2š‘— Ģ‚" + " š‘˜ Ģ‚))/3 = (āˆ’2š‘– Ģ‚ + 2š‘— Ģ‚ + 2š‘˜ Ģ‚ + š‘– Ģ‚ + 2š‘— Ģ‚ āˆ’( š‘˜) Ģ‚)/3 = (āˆ’š‘– Ģ‚ + 4š‘— Ģ‚ + š‘˜ Ģ‚)/3 Thus, position vector of R dividing P and Q internally is (āˆ’šŸ)/šŸ‘ š’Š Ģ‚ + šŸ’/šŸ‘ š’Š Ģ‚ + šŸ/šŸ‘ š’Œ Ģ‚ Ex 10.2, 15 Find the position vector of a point R which divides the line joining two points P and Q whose position vectors are š‘– Ģ‚ + 2 š‘— Ģ‚ āˆ’ š‘˜ Ģ‚ and – š‘– Ģ‚ + š‘— Ģ‚ + š‘˜ Ģ‚ respectively, in the ratio 2 : 1 (ii) externally Position vector of R = (2(š‘‚š‘„) āƒ— āˆ’ 1(š‘‚š‘ƒ) āƒ—)/(2 āˆ’ 1) (š‘‚š‘…) āƒ— = (2(āˆ’š‘– Ģ‚" + " š‘— Ģ‚" + " š‘˜ Ģ‚ )āˆ’1(š‘– Ģ‚" + " 2š‘— Ģ‚" āˆ’ " š‘˜ Ģ‚))/(2āˆ’1) (š‘‚š‘…) āƒ— = (āˆ’2š‘– Ģ‚ + 2š‘— Ģ‚ + 2š‘˜ Ģ‚ āˆ’ š‘– Ģ‚ āˆ’ 2š‘— Ģ‚ + š‘˜ Ģ‚)/(2āˆ’1) (š‘‚š‘…) āƒ— = –3š’Š Ģ‚ + 3š’Œ Ģ‚ Thus, Position vector of R dividing P and Q externally is āˆ’3š‘– Ģ‚ + 3š‘˜ Ģ‚

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