Check sibling questions

Ex 8.1, 7 - Chapter 8 Class 12 Application of Integrals (Term 2)

Last updated at March 22, 2023 by

Ex 8.1, 7 Find area of smaller part of circle x2 + y2 = a2 cutoff - Ex 8.1

Ex 8.1, 7 - Chapter 8 Class 12 Application of Integrals - Part 2
Ex 8.1, 7 - Chapter 8 Class 12 Application of Integrals - Part 3 Ex 8.1, 7 - Chapter 8 Class 12 Application of Integrals - Part 4

This video is only available for Teachoo black users

Subscribe Now

Get live Maths 1-on-1 Classs - Class 6 to 12

Book 30 minute class for ₹ 499 ₹ 299

Transcript

Ex 8.1, 7 Find the area of the smaller part of the circle 2+ 2= 2 cut off by the line = 2 . Equation of Given Circle is 2 + 2 = 2 Radius , = So, a is positive = 2 will lie on positive side of x-axis Let PQ represent the line = 2 We have to find Area of APQ Area APQ = 2 Area APR = 2 We know that, 2 + 2 = 2 2 = 2 2 = 2 2 Since , APR is in 1st Quadrant = 2 2 Area of APQ = 2 = 2 = 2 1 2 2 2 + 2 sin 1 2 = 2 2 2 2 + 2 2 sin 1 2 2 2 2 2 2 2 sin 1 2 = 2 0+ 2 2 sin 1 1 2 2 2 2 2 2 2 sin 1 1 2 = 2 2 2 1 1 2 2 sin 1 1 2 2 2 2 2 2 2 = 2 2 2 sin 1 1 sin 1 1 2 2 2 2 2 = 2 2 2 2 4 2 2 2 = 2 2 2 2 4 2 2.2 = 2 2 2 4 2 4 = 2 2 4 2 1 = 2 2 2 1 Required Area = Square units

Ask a doubt
Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.