# Ex 8.1, 7 - Chapter 8 Class 12 Application of Integrals

Last updated at May 29, 2018 by Teachoo

Last updated at May 29, 2018 by Teachoo

Transcript

Ex 8.1, 7 Find the area of the smaller part of the circle 2+ 2= 2 cut off by the line = 2 . Equation of Given Circle is 2 + 2 = 2 Radius , = So, a is positive = 2 will lie on positive side of x-axis Let PQ represent the line = 2 We have to find Area of APQ Area APQ = 2 Area APR = 2 We know that, 2 + 2 = 2 2 = 2 2 = 2 2 Since , APR is in 1st Quadrant = 2 2 Area of APQ = 2 = 2 = 2 1 2 2 2 + 2 sin 1 2 = 2 2 2 2 + 2 2 sin 1 2 2 2 2 2 2 2 sin 1 2 = 2 0+ 2 2 sin 1 1 2 2 2 2 2 2 2 sin 1 1 2 = 2 2 2 1 1 2 2 sin 1 1 2 2 2 2 2 2 2 = 2 2 2 sin 1 1 sin 1 1 2 2 2 2 2 = 2 2 2 2 4 2 2 2 = 2 2 2 2 4 2 2.2 = 2 2 2 4 2 4 = 2 2 4 2 1 = 2 2 2 1 Required Area = Square units

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.