Ex 8.1, 7 Find area of smaller part of circle x2 + y2 = a2 cutoff - Ex 8.1

Ex 8.1, 7 - Chapter 8 Class 12 Application of Integrals - Part 2
Ex 8.1, 7 - Chapter 8 Class 12 Application of Integrals - Part 3 Ex 8.1, 7 - Chapter 8 Class 12 Application of Integrals - Part 4

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Question 5 Find the area of the smaller part of the circle 2+ 2= 2 cut off by the line = 2 . Equation of Given Circle is 2 + 2 = 2 Radius , = So, a is positive = 2 will lie on positive side of x-axis Let PQ represent the line = 2 We have to find Area of APQ Area APQ = 2 Area APR = 2 We know that, 2 + 2 = 2 2 = 2 2 = 2 2 Since , APR is in 1st Quadrant = 2 2 Area of APQ = 2 = 2 = 2 1 2 2 2 + 2 sin 1 2 = 2 2 2 2 + 2 2 sin 1 2 2 2 2 2 2 2 sin 1 2 = 2 0+ 2 2 sin 1 1 2 2 2 2 2 2 2 sin 1 1 2 = 2 2 2 1 1 2 2 sin 1 1 2 2 2 2 2 2 2 = 2 2 2 sin 1 1 sin 1 1 2 2 2 2 2 = 2 2 2 2 4 2 2 2 = 2 2 2 2 4 2 2.2 = 2 2 2 4 2 4 = 2 2 4 2 1 = 2 2 2 1 Required Area = Square units

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.